Bill Allombert on Thu, 18 Sep 2014 19:10:25 +0200

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Re: hyperelliptic curve zeta function

On Thu, Sep 18, 2014 at 05:50:28PM +0200, Andreas Enge wrote:
> Hello,
> congratulations for the new algorithm! One question: Does it work in
> characteristic 2, and if yes, how does one specify the curve (as it
> requires a coefficient in front of Y)?

No, it only work if p is larger or equal to the degree of the polynomial.
Also it does not work for singular curves.