Andreas Enge on Thu, 18 Sep 2014 17:50:37 +0200


[Date Prev] [Date Next] [Thread Prev] [Thread Next] [Date Index] [Thread Index]

Re: hyperelliptic curve zeta function


Hello,

congratulations for the new algorithm! One question: Does it work in
characteristic 2, and if yes, how does one specify the curve (as it
requires a coefficient in front of Y)?

Andreas