Ewan Delanoy on Thu, 24 Jan 2013 14:50:50 +0100

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Re : Field inclusion problem

> nffactor(B, A) would factor A(X) over the number field Q[b] / (B(b)).
> ( a few seconds on such small inputs )

I tried that and obtained the following output :

? nffactor(polynomial_called_b,polynomial_called_a)
  ***   at top-level: nffactor(polynomial_ca
  ***                 ^--------------------
  *** nffactor: incorrect polynomial in rnf function.
  ***   Break loop: type 'break' to go back to GP

I suppose itâs no use to do a âmy_field=nfinit(polynomial_called_b)â first ? The computation would be prohibitively long.