Re: I don't find the solution ...

[Bill Allombert <Bill.Allombert@math.u-bordeaux.fr>]

On Sun, Dec 04, 2022 at 02:02:57AM +0100, Jean-Luc ARNAUD wrote:
> Hi,
> 
> Working with eval, I get the expected result with:
> 
>     eval([ a=((6*k)!*(-1)^k)/(((3*k)!*(k!)^3)*640320^(3*k)), k*a ]);
> 
> But I don't achieve the same calculation with pareval.

You cannot do this computation in parallel, simply because
you cannot compute k*a before having computed a.

Cheers,
Bill.