I don't find the solution ...

[Jean-Luc ARNAUD <jl.arnaud@free.fr>]

Hi,

Working with eval, I get the expected result with:

    eval([ a=((6*k)!*(-1)^k)/(((3*k)!*(k!)^3)*640320^(3*k)), k*a ]);

But I don't achieve the same calculation with pareval.

I'm using ()-> for the first equation, but what should I use for the second?

I tried:

    pareval([ (a)->((6*k)!*(-1)^k)/(((3*k)!*(k!)^3)*640320^(3*k)), 
()->k*a ]));

or:

    eval([ ()->a=((6*k)!*(-1)^k)/(((3*k)!*(k!)^3)*640320^(3*k)), 
()->k*a ]));

The first pareval results in correct calculation of the first term, but 
the second term is always 0.

Thanks for your help.

--

Jean-Luc Arnaud