| Pari/GP Reference Documentation | Contents
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| ! * + +/- ++ - -- / Boolean operators Comparison Equality \# % \ \/ ^ bestappr bestapprPade bestapprnf bezout chinese cmp content contfrac contfracpnqn divrem gcd gcdext halfgcd lcm lex max min op= shift shiftmul sign vecmax vecmin | |
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This section documents Boolean operators, comparison operators, and arithmetic operators. We also include variants on Euclidean division over the integers or polynomial rings, the Euclidean algorithm and standard applications : gcd, lcm, Chinese remainders, continued fractions, Padé approximants, etc.
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| Boolean operators |
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Any nonzero value is interpreted as true and any zero as false
(this includes empty vectors or matrices). The standard boolean operators
? a && b \\ 1 iff a and b are nonzero ? a || b \\ 1 iff a or b is nonzero ? !a \\ 1 iff a is zero
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| Comparison |
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The standard real comparison operators
By extension, two character strings (
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| Equality |
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Two operators allow to test for equality:
The operator
? 4 == Mod(1,3) \\ equal %1 = 1 ? 4 === Mod(1,3) \\ but not identical %2 = 0 ? 'x == 'y \\ not equal (nonconstant and different variables) %3 = 0 ? Pol(0,'x) == Pol(0,'y) \\ equal (constant: ignore variable) %4 = 1 ? Pol(0,'x) === Pol(0,'y) \\ not identical %5 = 0 ? 0 == Pol(0) \\ equal (not identical) %6 = 1 ? [0] == 0 \\ equal (not identical) %7 = 1 ? [0, 0] == 0 \\ equal (not identical) %8 = 1 ? [0] == [0,0] \\ not equal %9 = 0
In particular
Do not mistake
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| +/- |
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The expressions
The library syntax is
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| + |
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The expression x
The library syntax is
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| - |
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The expression x
The library syntax is
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| * |
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The expression x
Multiplication between two
? a = [1,2,3];
? a * a
*** at top-level: a*a
*** ^--
*** _*_: forbidden multiplication t_VEC * t_VEC.
? a * a~
%2 = 14
If x,y are binary quadratic forms, compose them; see also
The library syntax is
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| / |
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The expression x
The library syntax is
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| \ |
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The expression Note that when y is an integer and x a polynomial, y is first promoted to a polynomial of degree 0. When x is a vector or matrix, the operator is applied componentwise.
The library syntax is
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| \/ |
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The expression x When x is a vector or matrix, the operator is applied componentwise.
The library syntax is
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| % |
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The expression
? (1/2) % 3 %1 = 2 ? 0.5 % 3 %2 = 0.5000000000000000000000000000 ? (1/2) % 3.0 %3 = 1/2 Note that when y is an integer and x a polynomial, y is first promoted to a polynomial of degree 0. When x is a vector or matrix, the operator is applied componentwise.
The library syntax is
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| ! |
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The expression
The library syntax is
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| # |
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The expression
The library syntax is
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| op = |
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When
? v[1] += 10 \\ increment v[1] by 10 ? a /= 2 \\ divide a by 2
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| ++ |
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| -- |
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| ^ |
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The expression x^n is powering. * If the exponent n is an integer, then exact operations are performed using binary (left-shift) powering techniques. By definition, x0 is (an empty product interpreted as) an exact 1 in the underlying prime ring:
? 0.0 ^ 0 %1 = 1 ? (1 + O(2^3)) ^ 0 %2 = 1 ? (1 + O(x)) ^ 0 %3 = 1 ? Mod(2,4)^0 %4 = Mod(1,4) ? Mod(x,x^2)^0 %5 = Mod(1, x^2)
If x is a p-adic number, its precision will increase if vp(n) > 0 and
n != 0. Powering a binary quadratic form (type PARI rewrites the multiplication x * x of two identical objects as x2. Here, identical means the operands are reference the same chunk of memory; no equality test is performed. This is no longer true when more than two arguments are involved.
? a = 1 + O(2); b = a; ? a * a \\ = a^2, precision increases %2 = 1 + O(2^3) ? a * b \\ not rewritten as a^2 %3 = 1 + O(2) ? a*a*a \\ not rewritten as a^3 %4 = 1 + O(2) * If the exponent is a rational number p/q the behaviour depends on x. If x is a complex number, return exp(n log x) (principal branch), in an exact form if possible:
? 4^(1/2) \\ 4 being a square, this is exact %1 = 2 ? 2^(1/2) \\ now inexact %2 = 1.4142135623730950488016887242096980786 ? (-1/4)^(1/2) \\ exact again %3 = 1/2*I ? (-1)^(1/3) %4 = 0.500...+ 0.866...*I Note that even though -1 is an exact cube root of -1, it is not exp(log(-1)/3); the latter is returned. Otherwise return a solution y of yq = xp if it exists; beware that this is defined up to q-th roots of 1 in the base field. Intmods modulo composite numbers are not supported.
? Mod(7,19)^(1/2) %1 = Mod(11, 19) \\ is any square root ? sqrt(Mod(7,19)) %2 = Mod(8, 19) \\ is the smallest square root ? Mod(1,4)^(1/2) *** at top-level: Mod(1,4)^(1/2) *** ^ — — *** _^_: not a prime number in gpow: 4.
* If the exponent is a negative integer or rational number,
an inverse must be computed. For noninvertible
? Mod(4,6)^(-1)
*** at top-level: Mod(4,6)^(-1)
*** ^ — --
*** _^_: impossible inverse modulo: Mod(2, 6).
Here, a factor 2 is obtained directly. In general, take the gcd of the representative and the modulus. This is most useful when performing complicated operations modulo an integer N whose factorization is unknown. Either the computation succeeds and all is well, or a factor d is discovered and the computation may be restarted modulo d or N/d.
For noninvertible
? Mod(x^2, x^3-x)^(-1)
*** at top-level: Mod(x^2,x^3-x)^(-1)
*** ^ — --
*** _^_: impossible inverse in RgXQ_inv: Mod(x^2, x^3 - x).
Note that the underlying algorihm (subresultant) assumes that the base ring is a domain:
? a = Mod(3*y^3+1, 4); b = y^6+y^5+y^4+y^3+y^2+y+1; c = Mod(a,b);
? c^(-1)
*** at top-level: Mod(a,b)^(-1)
*** ^ — --
*** _^_: impossible inverse modulo: Mod(2, 4).
In fact c is invertible, but ℤ/4ℤ is not a domain and the algorithm fails. It is possible for the algorithm to succeed in such situations and any returned result will be correct, but chances are that an error will occur first. In this specific case, one should work with 2-adics. In general, one can also try the following approach
? inversemod(a, b) =
{ my(m, v = variable(b));
m = polsylvestermatrix(polrecip(a), polrecip(b));
m = matinverseimage(m, matid(#m)[,1]);
Polrev(m[1..poldegree(b)], v);
}
? inversemod(a,b)
%2 = Mod(2,4)*y^5 + Mod(3,4)*y^3 + Mod(1,4)*y^2 + Mod(3,4)*y + Mod(2,4)
This is not guaranteed to work either since
For a
? x = Mat([1;2]) %1 = [1] [2] ? x^(-1) %2 = [1 0] * Finally, if the exponent n is not a rational number, powering is treated as the transcendental function exp(nlog x), although it will be more precise than the latter when n and x are exact:
? s = 1/2 + 10^14 * I ? localprec(200); z = 2^s \\ for reference ? exponent(2^s - z) %3 = -127 \\ perfect ? exponent(exp(s * log(2)) - z) %4 = -84 \\ not so good The second computation is less precise because log(2) is first computed to 38 decimal digits, then multiplied by s, which has a huge imaginary part amplifying the error.
In this case, x
? 4 ^ 1.0 %1 = 4.0000000000000000000000000000000000000 ? 0^ 0.0 *** at top-level: 0^0.0 *** ^ — - *** _^_: domain error in gpow(0,n): n <= 0
The library syntax is
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| bestappr(x, {B}) |
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Using variants of the extended Euclidean algorithm, returns a rational
approximation a/b to x. If B is present, it must be a positive real
scalar and it imposes 0 < q ≤ B. If B is omitted, returns a good
approximation affordable given the input accuracy: for a
* If x is a
? bestappr(Pi, 100) %1 = 22/7 ? bestappr(0.1428571428571428571428571429) %2 = 1/7 ? bestappr([Pi, sqrt(2) + 'x], 10^3) %3 = [355/113, x + 1393/985] By definition, a/b is the best rational approximation to x if |b x - a| < |v x - u| for all integers (u,v) with 0 < v ≤ B. Which implies that a/b is either the last convergent pn/qn of the continued fraction of x with qn ≤ B or given by (pn-1 + tpn) / (qn-1 + tqn) for the largest integer t such that the denominator is ≤ B.
* If x is a
? bestappr(Mod(18526731858, 11^10)) %1 = 1/7 ? bestappr(Mod(18526731858, 11^20)) %2 = [] ? bestappr(3 + 5 + 3*5^2 + 5^3 + 3*5^4 + 5^5 + 3*5^6 + O(5^7)) %2 = -1/3 In most concrete uses, B is a prime power and we performed Hensel lifting to obtain x. The function applies recursively to components of complex objects (polynomials, vectors,...). If rational reconstruction fails for even a single entry, returns [].
The library syntax is
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| bestapprPade(x, {B}, {Q}) |
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Using variants of the extended Euclidean algorithm (Padé approximants), returns a rational function approximation a/b to x, whose denominator is limited by B, if present. If B is omitted, returns the best approximation affordable given the input accuracy; if you are looking for true rational functions, presumably approximated to sufficient accuracy, you should first try that option. Otherwise, B must be a nonnegative real (impose 0 ≤ degree(b) ≤ B).
* If x is a
? T = Mod(x^3 + x^2 + x + 3, x^4 - 2); ? bestapprPade(T) %2 = (2*x - 1)/(x - 1) ? U = Mod(1 + x + x^2 + x^3 + x^5, x^9); ? bestapprPade(U) \\ internally chooses B = 4 %3 = [] ? bestapprPade(U, 5) \\ with B = 5, a solution exists %4 = (2*x^4 + x^3 - x - 1)/(-x^5 + x^3 + x^2 - 1)
* If x is a
? T = 1 + t + t^2 + t^3 + t^4 + t^5 + t^6 + O(t^7); \\ mod t^7 ? bestapprPade(T) %1 = -1/(t - 1)
* If x is a
* If x is a
? T = (4*t^2 + 2*t + 3)/(t+1)^10; ? bestapprPade(T,1) %2 = [] \\ impossible ? bestapprPade(T,2) %3 = 27/(337*t^2 + 84*t + 9) ? bestapprPade(T,3) %4 = (4253*t - 3345)/(-39007*t^3 - 28519*t^2 - 8989*t - 1115) The function applies recursively to components of complex objects (polynomials, vectors,...). If rational reconstruction fails for even a single entry, return [].
The library syntax is
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| bestapprnf(V, T, {rootT}) |
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T being an integral polynomial and V being a scalar, vector, or
matrix with complex coefficients, return a reasonable approximation of V
with polmods modulo T. T can also be any number field structure, in which
case the minimal polynomial attached to the structure (
? bestapprnf(sqrt(5), polcyclo(5)) %1 = Mod(-2*x^3 - 2*x^2 - 1, x^4 + x^3 + x^2 + x + 1) ? bestapprnf(sqrt(5), polcyclo(5), exp(4*I*Pi/5)) %2 = Mod(2*x^3 + 2*x^2 + 1, x^4 + x^3 + x^2 + x + 1)
When the output has huge rational coefficients, try to
increase the working
? T = x^3-2; vT = polroots(T); z = 3*2^(1/3)+1; ? bestapprnf(z, T, vT[1]) %2 = Mod(3*x + 1, x^3 - 2) ? bestapprnf(z, T, vT[2]) %3 = 4213714286230872/186454048314072 \\ close to 3*2^(1/3) + 1
The library syntax is
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| bezout(x, y) |
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Deprecated alias for
The library syntax is
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| chinese(x, {y}) |
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If x and y are both intmods or both polmods, creates (with the same type) a z in the same residue class as x and in the same residue class as y, if it is possible.
? chinese(Mod(1,2), Mod(2,3)) %1 = Mod(5, 6) ? chinese(Mod(x,x^2-1), Mod(x+1,x^2+1)) %2 = Mod(-1/2*x^2 + x + 1/2, x^4 - 1) This function also allows p-adics pv (u + O(pd)) of non-negative valuation v, converted to the obvious intmod pv u modulo pv+d and O(pv) is converted to 0 modulo pv.
? chinese(1 + O(2), 2 + O(3)) %3 = Mod(5, 6) Finally, we allow vector and matrix arguments of same dimensions, in which case the operation is recursively applied to each component of the vector or matrix.
? chinese([Mod(1,2),Mod(1,3)], [Mod(1,5),Mod(2,7)]) %3 = [Mod(1, 10), Mod(16, 21)] ? M = mathilbert(3); ? chinese(Mod(M,7), Mod(M,11)) %4 = [ Mod(1, 77) Mod(39, 77) Mod(26, 77)] [Mod(39, 77) Mod(26, 77) Mod(58, 77)] [Mod(26, 77) Mod(58, 77) Mod(31, 77)] For polynomial arguments in the same variable, the function is applied to each coefficient. If the polynomials have different degrees, the high degree terms are understood as 0 modulo N if the low degree terms are defined mod N:
? chinese((x+1)*Mod(1,2), (x^2+2*x+1)*Mod(1,3)) %3 = Mod(4, 6)*x^2 + Mod(5, 6)*x + Mod(3, 6)
If y is omitted, and x is a vector,
Finally
The library syntax is
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| cmp(x, y) |
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Gives the result of a comparison between arbitrary objects x and y
(as -1, 0 or 1). The underlying order relation is transitive,
the function returns 0 if and only if x
* two
* two
* two In case all components are equal up to the smallest length of the operands, the more complex is considered to be larger. More precisely, the longest is the largest; when lengths are equal, we have matrix > vector > scalar. For example:
? cmp(1, 2) %1 = -1 ? cmp(2, 1) %2 = 1 ? cmp(1, 1.0) \\ note that 1 == 1.0, but (1===1.0) is false. %3 = -1 ? cmp(x + Pi, []) %4 = -1
This function is mostly useful to handle sorted lists or
vectors of arbitrary objects. For instance, if v is a vector, the
construction
The library syntax is
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| content(x, {D}) |
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Computes the gcd of all the coefficients of x, when this gcd makes sense. This is the natural definition if x is a polynomial (and by extension a power series) or a vector/matrix. This is in general a weaker notion than the ideal generated by the coefficients:
? content(2*x+y) %1 = 1 \\ = gcd(2,y) over Q[y]
If x is a scalar, this simply returns the absolute value of x if x is
rational ( The content of a rational function is the ratio of the contents of the numerator and the denominator. In recursive structures, if a matrix or vector coefficient x appears, the gcd is taken not with x, but with its content:
? content([ [2], 4*matid(3) ]) %1 = 2
The content of a The optional argument D allows to control over which ring we compute and get a more predictable behaviour: * 1: we only consider the underlying ℚ-structure and the denominator is a (positive) rational number
* a simple variable, say
? f = x + 1/y + 1/2; ? content(f) \\ as a t_POL in x %2 = 1/(2*y) ? content(f, 1) \\ Q-content %3 = 1/2 ? content(f, y) \\ as a rational function in y %4 = 1/2 ? g = x^2*y + y^2*x; ? content(g, x) %6 = y ? content(g, y) %7 = x
The library syntax is
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| contfrac(x, {b}, {nmax}) |
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Returns the row vector whose components are the partial quotients of the continued fraction expansion of x. In other words, a result [a0,...,an] means that x ~ a0+1/(a1+...+1/an). The output is normalized so that an != 1 (unless we also have n = 0).
If x is a real
The number of partial quotients n+1 is limited by
If x is a real
? \p19
realprecision = 19 significant digits
? contfrac(Pi)
%1 = [3, 7, 15, 1, 292, 1, 1, 1, 2, 1, 3, 1, 14, 2, 1, 1, 2, 2]
? contfrac(Pi,, 3) \\ n = 2
%2 = [3, 7, 15]
? w=quadgen(4*114);
? contfrac(w,,20)
%4 = [10,1,2,10,2,1,20,1,2,10,2,1,20,1,2,10,2,1,20,1]
? contfrac(w)
%5 = [[10],[1,2,10,2,1,20]]
x can also be a rational function or a power series.
If a vector b is supplied, the numerators are equal to the coefficients
of b, instead of all equal to 1 as above; more precisely, x ~
(1/b0)(a0+b1/(a1+...+bn/an)); for a numerical continued
fraction (x real), the ai are integers, as large as possible;
if x is a
rational function, they are polynomials with deg ai = deg bi + 1.
The length of the result is then equal to the length of b, unless the next
partial quotient cannot be reliably computed, in which case the expansion
stops. This happens when a partial remainder is equal to zero (or too small
compared to the available significant digits for x a
A direct implementation of the numerical continued fraction
\\ "greedy" generalized continued fraction
cf(x, b) =
{ my( a= vector(#b), t );
x *= b[1];
for (i = 1, #b,
a[i] = floor(x);
t = x - a[i]; if (!t || i == #b, break);
x = b[i+1] / t;
); a;
}
There is some degree of freedom when choosing the ai; the program above can easily be modified to derive variants of the standard algorithm. In the same vein, although no builtin function implements the related Engel expansion (a special kind of Egyptian fraction decomposition: x = 1/a1 + 1/(a1a2) +...), it can be obtained as follows:
\\ n terms of the Engel expansion of x
engel(x, n = 10) =
{ my( u = x, a = vector(n) );
for (k = 1, n,
a[k] = ceil(1/u);
u = u*a[k] - 1;
if (!u, break);
); a
}
Obsolete hack. (don't use this): if b is an integer, nmax
is ignored and the command is understood as
The library syntax is
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| contfracpnqn(x, {n = -1}) |
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When x is a vector or a one-row matrix, x is considered as the list of partial quotients [a0,a1,...,an] of a rational number, and the result is the 2 by 2 matrix [pn,pn-1;qn,qn-1] in the standard notation of continued fractions, so pn/qn = a0+1/(a1+...+1/an). If x is a matrix with two rows [b0,b1,...,bn] and [a0,a1,...,an], this is then considered as a generalized continued fraction and we have similarly pn/qn = (1/b0)(a0+b1/(a1+...+bn/an)). Note that in this case one usually has b0 = 1. If n ≥ 0 is present, returns all convergents from p0/q0 up to pn/qn. (All convergents if x is too small to compute the n+1 requested convergents.)
? a = contfrac(Pi,10) %1 = [3, 7, 15, 1, 292, 1, 1, 1, 3] ? allpnqn(x) = contfracpnqn(x,#x) \\ all convergents ? allpnqn(a) %3 = [3 22 333 355 103993 104348 208341 312689 1146408] [1 7 106 113 33102 33215 66317 99532 364913] ? contfracpnqn(a) \\ last two convergents %4 = [1146408 312689] [ 364913 99532] ? contfracpnqn(a,3) \\ first three convergents %5 = [3 22 333 355] [1 7 106 113]
The library syntax is
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| divrem(x, y, {v}) |
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Creates a column vector with two components, the first being the Euclidean
quotient (
Beware that
? divrem(1/2, 3)[2] %1 = 1/2 ? (1/2) % 3 %2 = 2 ? divrem(Mod(2,9), 3)[2] *** at top-level: divrem(Mod(2,9),3)[2 *** ^ — — — — — — -- *** forbidden division t_INTMOD \ t_INT. ? Mod(2,9) % 6 %3 = Mod(2,3)
The library syntax is
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| gcd(x, {y}) |
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Creates the greatest common divisor of x and y.
If you also need the u and v such that x*u + y*v = gcd(x,y),
use the
When x and y are both given and one of them is a vector/matrix type,
the GCD is again taken recursively on each component, but in a different way.
If y is a vector, resp. matrix, then the result has the same type as y,
and components equal to The algorithm used is a naive Euclid except for the following inputs: * integers: use modified right-shift binary ("plus-minus" variant). * univariate polynomials with coefficients in the same number field (in particular rational): use modular gcd algorithm. * general polynomials: use the subresultant algorithm if coefficient explosion is likely (non modular coefficients). If u and v are polynomials in the same variable with inexact coefficients, their gcd is defined to be scalar, so that
? a = x + 0.0; gcd(a,a) %1 = 1 ? b = y*x + O(y); gcd(b,b) %2 = y ? c = 4*x + O(2^3); gcd(c,c) %3 = 4
A good quantitative check to decide whether such a
gcd "should be" nontrivial, is to use
The library syntax is
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| gcdext(x, y) |
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Returns [u,v,d] such that d is the gcd of x,y, x*u+y*v = gcd(x,y), and u and v minimal in a natural sense. The arguments must be integers or polynomials.
? [u, v, d] = gcdext(32,102) %1 = [16, -5, 2] ? d %2 = 2 ? gcdext(x^2-x, x^2+x-2) %3 = [-1/2, 1/2, x - 1]
If x,y are polynomials in the same variable and inexact
coefficients, then compute u,v,d such that x*u+y*v = d, where d
approximately divides both and x and y; in particular, we do not obtain
? a = x + 0.0; gcd(a,a) %1 = 1 ? gcdext(a,a) %2 = [0, 1, x + 0.E-28] ? gcdext(x-Pi, 6*x^2-zeta(2)) %3 = [-6*x - 18.8495559, 1, 57.5726923] For inexact inputs, the output is thus not well defined mathematically, but you obtain explicit polynomials to check whether the approximation is close enough for your needs.
The library syntax is
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| halfgcd(x, y) |
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Let inputs x and y be both integers, or both polynomials in the same
variable. Return a vector * polynomial case: det M has degree 0 and we have deg a ≥ ceil{max(deg x,deg y))/2} > deg b. * integer case: det M = ± 1 and we have a ≥ ceil{sqrt{max(|x|,|y|)}} > b. Assuming x and y are nonnegative, then M-1 has nonnegative coefficients, and det M is equal to the sign of both main diagonal terms M[1,1] and M[2,2].
The library syntax is
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| lcm(x, {y}) |
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Least common multiple of x and y, i.e. such that lcm(x,y)*gcd(x,y) = x*y, up to units. If y is omitted and x is a vector, returns the lcm of all components of x. For integer arguments, return the nonnegative lcm.
When x and y are both given and one of them is a vector/matrix type,
the LCM is again taken recursively on each component, but in a different way.
If y is a vector, resp. matrix, then the result has the same type as y,
and components equal to
Note that
l = v[1]; for (i = 1, #v, l = lcm(l, v[i]))
Indeed,
? v = vector(10^5, i, random); ? lcm(v); time = 546 ms. ? l = v[1]; for (i = 1, #v, l = lcm(l, v[i])) time = 4,561 ms.
The library syntax is
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| lex(x, y) |
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Gives the result of a lexicographic comparison between x and y (as -1, 0 or 1). This is to be interpreted in quite a wide sense: it is admissible to compare objects of different types (scalars, vectors, matrices), provided the scalars can be compared, as well as vectors/matrices of different lengths; finally, when comparing two scalars, a complex number a + I*b is interpreted as a vector [a,b] and a real number a as [a,0]. The comparison is recursive. In case all components are equal up to the smallest length of the operands, the more complex is considered to be larger. More precisely, the longest is the largest; when lengths are equal, we have matrix > vector > scalar. For example:
? lex([1,3], [1,2,5]) %1 = 1 ? lex([1,3], [1,3,-1]) %2 = -1 ? lex([1], [[1]]) %3 = -1 ? lex([1], [1]~) %4 = 0 ? lex(2 - I, 1) %5 = 1 ? lex(2 - I, 2) %6 = -1
The library syntax is
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| max(x, y) |
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Creates the maximum of x and y when they can be compared.
The library syntax is
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| min(x, y) |
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Creates the minimum of x and y when they can be compared.
The library syntax is
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| shift(x, n) |
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Shifts x componentwise left by n bits if n ≥ 0 and right by |n|
bits if n < 0. May be abbreviated as x
The library syntax is
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| shiftmul(x, n) |
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Multiplies x by 2n. The difference with
The library syntax is
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| sign(x) |
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sign (0, 1 or -1) of x, which must be of
type integer, real or fraction;
The library syntax is
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| vecmax(x, {&v}) |
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If x is a list, vector or matrix, returns the largest entry of x,
otherwise returns a copy of x. Error if x is empty. Here, largest
refers to the ordinary real ordering ( If v is given, set it to the index of a largest entry (indirect maximum), when x is a vector or list. If x is a matrix, set v to coordinates [i,j] such that x[i,j] is a largest entry. This argument v is ignored for other types. When the vector has equal largest entries, the first occurence is chosen; in a matrix, the smallest j is chosen first, then the smallest i. vector or matrix.
? vecmax([10, 20, -30, 40]) %1 = 40 ? vecmax([10, 20, -30, 40], &v); v %2 = 4 ? vecmax([10, 20; -30, 40], &v); v %3 = [2, 2]
The library syntax is
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| vecmin(x, {&v}) |
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If x is a list, vector or matrix, returns the smallest entry of x,
otherwise returns a copy of x. Error if x is empty. Here, smallest
refers to the ordinary real ordering ( If v is given, set it to the index of a smallest entry (indirect minimum), when x is a vector or list. If x is a matrix, set v to coordinates [i,j] such that x[i,j] is a smallest entry. This argument v is ignored for other types. When a vector has equal smallest entries, the first occurence is chosen; in a matrix, the smallest j is chosen first, then the smallest i.
? vecmin([10, 20, -30, 40]) %1 = -30 ? vecmin([10, 20, -30, 40], &v); v %2 = 3 ? vecmin([10, 20; -30, 40], &v); v %3 = [2, 1] ? vecmin([1,0;0,0], &v); v %3 = [2, 1]
The library syntax is
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