Bill Allombert on Fri, 02 Nov 2007 12:06:16 +0100 |
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Re: Gcd in Z[I] |
On Thu, Nov 01, 2007 at 12:53:10PM +0100, Olivier Ramare wrote: > Dear all, > > I simply would like to check that I'm not > doing any mistake: gcd answers the gcd in Z[I] > when the arguments are in Z[I], correct? Yes. Also since the gcd of two integers is the same computed over Z or Z[i], this is safe, as opposed to factor: ? factor(x^2+4+0*I) %13 = [x - 2*I 1] [x + 2*I 1] ? factor(x^2+4) %14 = [x^2 + 4 1] Cheers, Bill.