| Aurel Page on Thu, 12 Mar 2026 15:41:09 +0100 |
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| Re: S-Unit questions |
On 3/12/26 15:36, hermann@stamm-wilbrandt.de wrote:
This solution is a hallucination: we do not currently have an S-unit equation solver in PARI, though it would be interesting to have one.This is the script proposed by Gemini, which errors on bnfuniteqn() not existing:So how to solve this equation using PARI/GP with its Baker(?) algorithm?±2^{a1}*3^{b1}±2^{a2}*3^{b2}=1? { \\ 1. Initialize Q bnf = bnfinit(x - 1); \\ 2. Define S = {2, 3} correctly S = concat([idealprimedec(bnf, 2), idealprimedec(bnf, 3)]);\\ 3. Get the S-unit structure AND the map (the '1' at the end is vital)s_struct = bnfsunit(bnf, S); \\ 4. Solve the S-unit equation epsilon_1 + epsilon_2 = 1\\ This returns the solutions as exponent vectors relative to the S-unit generatorssolutions_vecs = bnfuniteqn(s_struct); \\ 5. Convert exponent vectors back into actual rational numbers \\ s_struct[1] contains the generators: [-1, 2, 3] gens = s_struct[1]; print("Solutions (x, y) where x + y = 1:"); for(i = 1, #solutions_vecs, sol = solutions_vecs[i]; \\ The solution is a pair [x, y] x = nfeltfactorback(bnf, gens, sol[1]); y = nfeltfactorback(bnf, gens, sol[2]); print([x, y]); ); } *** at top-level: ...it(bnf,S);solutions_vecs=bnfuniteqn(s_struct); *** ^--------------------- *** not a function in function call *** Break loop: type 'break' to go back to GP prompt break>
Cheers, Aurel