| Kurt Foster on Thu, 22 Jan 2026 19:53:46 +0100 |
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| Re: Computation with two algebraic integers |
On Jan 22, 2026, at 9:24 AM, Ewan Delanoy wrote:
minpoly_for_h=h^6 - 3*h^4 + 3*h^2 - 3 minpoly_for_g=g^3-2
I note that minpoly_for_h = (h-1)^3 - 2. This looks suspiciously like the minpoly_for_g.