Thomas D. Dean on Mon, 27 Nov 2023 08:39:51 +0100 |
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Re: asking for a simple locally soluble algorithm for a quartic |
On 11/26/23 23:22, Thomas D. Dean wrote:
On 11/26/23 17:44, American Citizen wrote:Does anyone have a simple GP-Pari script which outputs 0 for false and 1 for true when the input is a quartic in vector format: [a,b,c,d,e] where the quartic is a*x^4 + b*x^3 + c^x^2 + d^x +e and we are trying to find the everywhere_local_solubility of the quartic?look at polsturmExample GP Pari function:everywhere_locally_soluble(Q) = [0,1] where 0 means false and 1 means true.
for real roots Sorry, I hit send too soon Some hints in: https://en.wikipedia.org/wiki/Quartic_equation Tom Dean