Aurel Page on Wed, 12 Apr 2023 09:25:59 +0200 |
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Re: Find an invertible integer matrix that satisfies given conditions. |
Sorry, I missed the determinant condition. That definitely makes it harder (that being a quartic condition).
On Tue, Apr 11, 2023 at 11:01 PM Charles Greathouse <crgreathouse@gmail.com> wrote:
Playing around with linear algebra gives, as an example,[4,-1,1,4; 4, 4, 0, 5; 4, -1, 5, 4; 4, 4, 0, 9]
There are 8 degrees of freedom here so you have lots of choices to make.
I'll let the real PARI experts suggest code here.
On Tue, Apr 11, 2023 at 9:21 PM Hongyi Zhao <hongyi.zhao@gmail.com> wrote:
Hi here,
I am trying to write a script to find a matrix that satisfies certain
conditions. Specifically, I am trying to find an n x n matrix M that
satisfies the following two conditions:
1. The determinant of M is either 1 or -1.
2. M1 * M = M * M2, where M1 and M2 are two pre-defined matrices.
I have written the following code, but it can't solve the problem:
```
/* Define the two matrices */
M1 = [0, 1, 0, 0; -4, 0, 0, 0; 0, 0, 0, 1; 0, 0, -4, 0];
M2 = [0, 1, 4, 0; -4, 0, 0, -4; 0, 0, 0, 1; 0, 0, -4, 0];
/* Set the size of the matrix */
n = 4;
/* Initialize a flag variable to check if a solution has been found */
flag = 0;
/* Loop until a solution is found */
while(flag == 0,
/* Generate a random integer matrix */
M = matrix(n,n,i,j,random(-10,10));
/* Check if the matrix satisfies the conditions */
if(abs(Mat(det(M))) == 1 && Mat(M1 * M) == Mat(M * M2),
/* If the conditions are satisfied, print the matrix and exit
the loop */
print("Found solution:");
print(M);
flag = 1;
);
);
```
In fact, this is a harder problem as described here [1], I'm not sure
whether it's possible to tackle it in PARI/GP? Thank you in advance
for your help.
[1] https://arxiv.org/abs/1811.06190
Best regards,
Zhao
--
Assoc. Prof. Hongsheng Zhao <hongyi.zhao@gmail.com>
Theory and Simulation of Materials
Hebei Vocational University of Technology and Engineering
No. 473, Quannan West Street, Xindu District, Xingtai, Hebei province