Ruud H.G. van Tol on Wed, 22 Mar 2023 10:01:27 +0100 |
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Re: defining a recurrence |
On 2023-03-22 02:27, Anders Hellström wrote:
Factorial with or without recurrence. fact1(n)=my(m);if(n==1,m=1,m=n*fact1(n-1));m \\recurrence
For "technical/implementation reasons" it is likely better to define such as fact1(n)= if(1==n, return(1)); n * fact1(n-1) For example test with 10^4. -- Ruud