Karim Belabas on Sat, 16 Nov 2013 22:50:47 +0100 |
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Re: Shorter way to convert polynomial in x^3 to x? |
* Richard Heylen [2013-11-16 22:43]: > ? f=factor(elldivpol(ellinit([0,1]),13))[1,1] > %32 = 13*x^12 + 52*x^9 + 1536*x^6 + 1024*x^3 + 256 > ? Pol(vector(poldegree(f)/3+1,i,polcoeff(f,poldegree(f)-3*i+3))) > %33 = 13*x^4 + 52*x^3 + 1536*x^2 + 1024*x + 256 > > > I tried using subst(f,x,y^(1/3)) but to no avail. Is there a short way > of doing this? (22:50) gp > substpol(f,x^3,x) %2 = 13*x^4 + 52*x^3 + 1536*x^2 + 1024*x + 256 Cheers, K.B. -- Karim Belabas, IMB (UMR 5251) Tel: (+33) (0)5 40 00 26 17 Universite Bordeaux 1 Fax: (+33) (0)5 40 00 69 50 351, cours de la Liberation http://www.math.u-bordeaux1.fr/~kbelabas/ F-33405 Talence (France) http://pari.math.u-bordeaux1.fr/ [PARI/GP] `