modulus a+b*I

["Perry S. Glenn" <psglenn@yahoo.com>]

Hello,
I would expect to get the result

z=a+b*I
abs(z)= a^2+b^2

but instead ...

Script started on Sun Jul  1 00:57:16 2001
[root@big root]#gp
                  GP/PARI CALCULATOR Version 2.1.1 (released)
               i686 running freebsd (ix86 kernel) 32-bit version
                (readline v4.1 enabled, extended help available)

                       Copyright (C) 2000 The PARI Group

PARI/GP is free software, covered by the GNU General Public License,
and 
comes WITHOUT ANY WARRANTY WHATSOEVER.

Type ? for help, \q to quit.
Type ?12 for how to get moral (and possibly technical) support.

   realprecision = 28 significant digits
   seriesprecision = 16 significant terms
   format = g0.28

parisize = 4000000, primelimit = 500000
? z=a+I*b
%1 = a + I*b
? abs(z)
%2 = a + I*b
? \q
Good bye!
[root@big root]#exit

Script done on Sun Jul  1 00:57:47 2001

I've also gotten the same answer using Version 2.2.0 (Alpha).

Thank you,
		PSGlenn.


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