Re: Turning a sequence of expr into expr

[Ilya Zakharevich <ilya@math.ohio-state.edu>]

On Fri, Nov 12, 1999 at 02:29:59PM +0100, Bill Allombert wrote:
> It is perfectly true, it's the difference between a 'seq' and an 'expr'
> an 'expr' cannot contains ';' 
> 
> ? ?ploth
> ploth(X=a,b,expr,{flags=0},{n=0}):
>             ^^^^
> ? ?for
> for(X=a,b,seq):
>           ^^^
> 
> Only true control statements handle seq ,if,forxxx, while,until
> but not sumxxx,prodx,solve,intnum etc..

Then this should be marked in the "prototype", and the parser should
emit a syntax error in such a situation.  The simplest way to do it is
to make lisexpr() to die if it finds ';' at the end, and make lisseq()
use a clone lisexpr_seqok() instead.

Ilya