Bill Allombert on Tue, 17 Jul 2012 14:15:29 +0200 |
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(Mod(1,2)*x*y)^0 |
Dear PARI developers, We hae the following behavior : ? Mod(1,2)^0 %1 = Mod(1,2) ? (Mod(1,2)*x)^0 %2 = Mod(1,2) ? (Mod(1,2)*x*y)^0 %3 = 1 Is it intended ? Cheers, Bill.