Bill Allombert on Tue, 09 Mar 2004 19:12:36 +0100

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freeall() does not free members_hash ?

Hello PARI-dev,

During the new parser experiment, I found that
freeall() probably miss a
free((void *)members_hash);

(By the way, gcc give a warning in subgroups.c line 290)


I have updated the experimental parser:
It support break(), return() and %n.
it pass the test-suite if we exclude all the getheap calls since I have
removed the kludges.