gp: a/b/c == (a/c)/b ?

Michael Somos on Fri, 28 Feb 2003 11:52:39 -0500

[Date Prev] [Date Next] [Thread Prev] [Thread Next] [Date Index] [Thread Index]

gp: a/b/c == (a/c)/b ?

To: pari-dev@list.cr.yp.to
Subject: gp: a/b/c == (a/c)/b ?
From: Michael Somos <somos@grail.cba.csuohio.edu>
Date: Fri, 28 Feb 2003 11:52:39 -0500

pari-dev

? a/b/c == a/c/b
%1 = 1
? c/a/b == (c/b)/a
%2 = 0

a difference which makes a difference. Shalom, Michael

Follow-Ups:
- Re: gp: a/b/c == (a/c)/b ?
  - From: Igor Schein <igor@txc.com>

Prev by Date: Re: gp: ellpow() pointers lost
Next by Date: Re: gp: a/b/c == (a/c)/b ?
Previous by thread: Re: gp: ellpow() pointers lost
Next by thread: Re: gp: a/b/c == (a/c)/b ?
Index(es):
- Date
- Thread