Bill Daly on Tue, 11 Feb 2003 15:53:21 -0500

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Re: gp: subst(x^2+x+1,x^2+1,x)

On Mon, 10 Feb 2003, Michael Somos wrote:
> ? subst(x^2+x+1,x^2+1,x)
> %1 = 2*x
> Is it supposed to do that?

This is consistent with Mod(x^2+x+1,x^2-x+1) == Mod(2*x,x^2-x+1).

Regards, Bill

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