Bill Allombert on Wed, 11 Dec 2002 20:38:26 +0100 |
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Re: How to eliminate the big-oh |
On Wed, Dec 11, 2002 at 02:26:13PM -0500, Michael Somos wrote: > Franck Michel writes : > > > but truncate(taylor((1-x)/(1-t),t)) does not eliminate the big-oh. > > True, but : > > ? print(truncate(taylor((1-t)/(1-x)+O(x^5),x))) > (-t + 1)*x^4 + (-t + 1)*x^3 + (-t + 1)*x^2 + (-t + 1)*x + (-t + 1) > > may be what you are looking for. Perhaps if you give an example of > desired output we could give an expression to produce it. Shalom, As Michael say, x has an higher priority than t and truncate only truncate with respect of the highest priority variable. This is a problem here. Assuming z has higher priority that x, you can do subst(truncate(subst(taylor((1-x)/(1-t),t),x,z)),z,x) fortunately there is a simpler solution, convert your polynomial to a vector: Pol(truncate(Vec(taylor((1-x)/(1-t),t)))) Cheers, Bill.