Bill Allombert on Sun, 11 May 2003 19:24:42 +0200 |
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Re: CVS: seriesprecision too large |
On Sat, May 10, 2003 at 03:29:23PM -0700, Ilya Zakharevich wrote: > ? default(seriesprecision,9) > seriesprecision = 9 significant terms ... > See the terms with y^10. It is fine with 2.2.0. I think it is 2.2.5 F22: 22- for transcendental function f and polynomial p, f(p) only gave seriesprecision significant terms when val(p) = 0 So this change is expected: Now ? sin(x) %1 = x - 1/6*x^3 + 1/120*x^5 - 1/5040*x^7 + 1/362880*x^9 - 1/39916800*x^11 + 1/6227020800*x^13 - 1/1307674368000*x^15 + O(x^17) instead of %1 = x - 1/6*x^3 + 1/120*x^5 - 1/5040*x^7 + 1/362880*x^9 - 1/39916800*x^11 + 1/6227020800*x^13 - 1/1307674368000*x^15 + O(x^16) the rationale geing that we do not count the leading zero as a significant term. Cheers, Bill.