Examples
F = Q(
√
36322, ζ5)
? T = polcompositum(x^2-36322, polcyclo(5), 2);
? bnfinit(T).cyc
time = 2,870 ms.
%7 = [2000, 20, 20, 2]
? subcyclopclgp(T, 5)
time = 89 ms.
%6 = [5, [1, [1]], [4, []], ...]
? subcyclopclgp(T, 5, 1+4)
time = 93 ms.
%7 = [5, [1, [1]], [], ...]
? default(parisizemax, "4G")
? subcyclopclgp(T, 5, 1)
time = 33,468 ms.
%9 = [5, [1, [1]], [4, [3, 1]], ...]
Atelier 2022 (13/01/2022) – p. 9/13